设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180°

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设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180°+x)+cos(-x),求f(π/3)的值
设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180°+x)+cos(-x),求f(π/3)的值

f(x)=[2cos³x+sin²(-x)+2cosx+1]/[2+2(-cosx)²+cosx]
=(2cos³x+sin²x+2cosx+1)/[2+2cos²x+cosx]
cosπ/3=1/2,sinπ/3=√3/2
f(π/3)=(1/4+3/4+1+1)/(2+1/2+1/2)=1

设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180° 求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x). 设函数f(x)=cos(2x+π/3)+sin^2x-1/2 设f=[sin(2/x)]=1+cosx,求f(x),f[cos(2/x)]. 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x 设函数f(x)=cos(2x+π/3)+sin^2 X 设函数f(x)=cos(2x+π/3)+sin^2x 急.设函数f(x)=cos(2x+π/3)+sin^2 X 设函数f(x)=cos(2x+pai/3)+sin^2x 设函数f(x)=cos(2x+π/3)+sin方x 1.设函数f(x)=cos(2x+π/3)+sin(平方)x 设函数f(x)=cos(2x+π/3)+sin²x