lim(x->0)ln(cosx)^1/x^2怎么算
lim(x->0)ln(cosx)^1/x^2怎么算
lim(x→0)(x^2+cosx-2)/(x^3)*ln(1+x)怎么算
lim (cosx)^ln(1/1+x^2)怎么算
求lim{下面(x属于0)}(1-cosx)/ln(1+x^2)的极限怎么算?
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)(ln(1+x^2)/(sec-cosx))
lim[ln(1+x^2)]/(secx-cosx) x->0
lim{[sinx+(x^2)*sin(1/x)]/[(1+cosx)ln(1+x)]}(x趋近于0)
lim{[3sinx+(x^2)*cos(1/x)]/[(1+cosx)ln(1+x)]}(x趋近于0)
lim(x趋于0)(1-cosx)/[ln(1+x)(e^x-1)]
求极限:lim(x趋向0) [1-cosx(cos2x)^1/2(cos3x)^1/3]/[ln(1+x)-x]
lim(x→0)(1-cosx)[x-ln(1+tanx)]/(sinx)^4