lim[ln(1+x^2)]/(secx-cosx) x->0

lim[ln(1+x^2)]/(secx-cosx) x->0 1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx 求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx limx趋向0[ln(1+x^2)/secx-cosx] lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x→0)(ln(1+x^2)/(sec-cosx)) lim(x→0) (ln cosx)/[ln(1+x^2)] 等于多少? lim(x->0)[cosx-e^(-x^2/2)]/[x^2[x+ln(1-x)]] lim x→0[ln(cosx)]/x^2 lim(x趋于0时)secx - 1/x^2 , lim x趋于0 (sinx+x^2sin1/x)/[(1+cosx)ln(1+x)] lim(x→0)(x^2+cosx-2)/(x^3)*ln(1+x)怎么算