求Lim(x→0)(sinx/x)^(cosx/1-cosx)
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求Lim(x→0)(sinx/x)^(cosx/1-cosx)
y=(sinx/x)^(cosx/1-cosx)
lny=(cosx(lnsinx-lnx)/(1-cosx)
limlny=lim(cosx(lnsinx-lnx)/(1-cosx)=lim(lnsinx-lnx)/(1-cosx)=lim(cosx/sinx-1/x)/sinx=lim(xcosx-sinx)/x^3=lim(cosx-xsinx-cosx)/3x^2=-1/3
limy=e^(-1/3)
再问: lim(cosx/sinx-1/x)/sinx=lim(xcosx-sinx)/x^3这个步骤怎么得到?
再答: 通分 lim(cosx/sinx-1/x)/sinx =lim(xcosx-sinx)/(xsinxsinx) =lim(xcosx-sinx)/x^3
lny=(cosx(lnsinx-lnx)/(1-cosx)
limlny=lim(cosx(lnsinx-lnx)/(1-cosx)=lim(lnsinx-lnx)/(1-cosx)=lim(cosx/sinx-1/x)/sinx=lim(xcosx-sinx)/x^3=lim(cosx-xsinx-cosx)/3x^2=-1/3
limy=e^(-1/3)
再问: lim(cosx/sinx-1/x)/sinx=lim(xcosx-sinx)/x^3这个步骤怎么得到?
再答: 通分 lim(cosx/sinx-1/x)/sinx =lim(xcosx-sinx)/(xsinxsinx) =lim(xcosx-sinx)/x^3
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