#define f(x) x*x main( ) { int i; i=f(4+4)/f(2+2); printf("%
#define f(x) x*x main( ) { int i; i=f(4+4)/f(2+2); printf("%
#define f(x) x*x main() {int a=6,b=2,c; C=f(a)?f(b); printf(
#define P3 void F(int x){return(P*x*x);} main() {printf("%d\
#define P 3 void F(int x){return(P*x*x);} main() {printf("%d
这道题就是看不明白(38) 有以下程序#define f(x) x*xmain( ){ int i; i=f(4+4)/
fun(int x) {if (x/2>0) fun(x/2); printf("%d",x); } main() {f
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
#include #define f(x) x*x main() {int a=6,b=2,c; c=f(a)/f(b)
C语言:二分法#include#define f(x) (x*x*x-2*x*x+3*x-4)void main(){
(35) 有以下程序#define P 3#define F(int x) { return (P*x*x);}main
#define F(x) x - 2 #define D(x) x*F(x) printf("%d,%d",D(3),D
# define MA(x,y) (x)*(y) int i=2; i=3/MA(i,i+2)+5; printf(“%