#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
#define S(x)4 *(x)*x+1 main() {int k=5,j=2;printf("%d\n",S(k
#include #define S(x) x*x void main() { int a,k=3,m=1; a=S(k
define M 5#define N M+M main(){int k;k=N*N*5; printf("%d",k)
main() {int x=10,i=1,j=2; printf (“%d,%o,%x\n”,x,x,x); print
void main() {int x=4;if(x++>=5)printf("%d/n",x);else printf(
3.设有以下程序:、#include #define S(X) X*Xvoid main(void){int k=2;c
#include #define S(x) x*x main() {int a=9,k=3,m=2; a/=S(k+m)
#include main() { int i=2,j=1,k=3; printf("%d\n",i && (i+j)&
、下面程序的输出是( ).main() { int k=13; printf(“k=%d,k=%o,k=%x\n”,k,
int x=10,y=20; main() { int k,y=5; k=f1(); printf("k=%d,x=%d
下面的程序的输出结果是() main(){int k=11;printf (''k=%d,k=%0,k=%x\n'');
若有宏定义# define s(x) x*x-x,设int k=3; 问cout