作业帮1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+...+1/(x-99)(
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/29 04:01:25
1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+...+1/(x-99)(x-100)
1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+...+1/(x-99)(x-100)
=1/(x-1)+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+.+1/(x-100)-1/(x-99)
=1/(x-100)
再问： 请问怎么得到第一步?
再答： 1/(x-1)(x-2)
=[(x-1)-(x-2)]/(x-1)(x-2)
=(x-1)/(x-1)(x-2)-(x-2)/(x-1)(x-2)
=1/(x-2)-1/(x-1)
后面的同理可得
=1/(x-1)+1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+.+1/(x-100)-1/(x-99)
=1/(x-100)
再问： 请问怎么得到第一步?
再答： 1/(x-1)(x-2)
=[(x-1)-(x-2)]/(x-1)(x-2)
=(x-1)/(x-1)(x-2)-(x-2)/(x-1)(x-2)
=1/(x-2)-1/(x-1)
后面的同理可得
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
1+x+x^2+x^3+.+x^99+x^100
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)
x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4)
分解公因式(1+X)+X(1+X)+X(1+X)^2+X(1+X)^3+...+X(1+X)^99
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
|x^2-3x-4|>x+1
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
1x+2x+3x+4x+5x+6x+7x…+99x=100
解方程：2x+4x+6x...+100x=1-(x+3x+5x+...+99x)