已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)求①化简f(α)

已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)求①化简f(α) ②若cos（已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan（-α）sin（-π 已知α是第三象限角,且f(α)=[sin(π+α)cos(2π-α)tan(-α+3π/2)tan(-α-π)]/sin 已知f=[sin(π-α)cos(2π-α)tan(-π-α)]/sin(-π-α),⑴化简f(a)、⑵若α是第三象限, 已知α是第三象限角,f(α)=[sin(π-a)cos(2π-a)tan(1.5π-a)tan(-a-π)]/sin(- 已知f(α)=sin(π-α)cos(2π-α)tan(π-α)/-tan(-π-α)sin(-π-α),若α是第三象限 已知α为第三象限角,且f(α)=sin(π-α)cos(2π-α)tan(-α+π)/sin(π+α)tan(2π-α) α是第三象限角,f(α)={sin（α-π/2）cos（3π/2+α）tan（π-α）}/{tan（-α-π）sin（- 已知α是第三象限角,且f(α)=sin（π-α)cos(2π-α)tan(-α+3π/2）/cos(-α -π) (1） 1.已知α是第二象限角,f(α)=[sin(3π/2-α)·cos(2π-α)·tan(π-α)]/-cos(-π-α) 已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α) 已知α是第三象限角,且f(α）=[sin（α-π/2)cos(3π/2+α）tan(π-α）]/[tan( -α-π）s