设x=ln(1+t²) y=t-arctant 求dy/dx d²y/dx²
设x=ln(1+t²) y=t-arctant 求dy/dx d²y/dx²
设{x=ln√(1+t^2),y=arctant,求 dy/dx及d^2·y/d·x^2
方程组 x=ln√1+t^2 y=arctant 求 dy/dx
x=ln(1+t^2),y=arctant+π 求dy/dx和d2y/dx2
设参数函数x=ln(1+t^2),y=t-arctant.求(d^2y)/(dx^2).
请高手赐教:设由参数方程:x=t-arctant;y=ln(1+t^2) 确定y是x的函数,求dy/dx.
求dy/dx.x=ln(1+t²),y=t-arctant求详细步骤.不要只给答案.
y=f(e^x) ,其中f具有二阶导数,求 dy/dx ,d²y/dx²
方程组 x=ln√1+t^2 y=arctant 求 dy/dx 包含了哪些知识点
=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2
x=ln(1+t^2),y=t-arctant 求d^2y/dx^2的导数,
求次微分方程的通解:y(1+x²)dy-x(1+y²)dx=0