设{x=ln√(1+t^2),y=arctant,求 dy/dx及d^2·y/d·x^2
设{x=ln√(1+t^2),y=arctant,求 dy/dx及d^2·y/d·x^2
设x=ln(1+t²) y=t-arctant 求dy/dx d²y/dx²
设参数函数x=ln(1+t^2),y=t-arctant.求(d^2y)/(dx^2).
方程组 x=ln√1+t^2 y=arctant 求 dy/dx
x=ln(1+t^2),y=arctant+π 求dy/dx和d2y/dx2
x=ln(1+t^2),y=t-arctant 求d^2y/dx^2的导数,
方程组 x=ln√1+t^2 y=arctant 求 dy/dx 包含了哪些知识点
请高手赐教:设由参数方程:x=t-arctant;y=ln(1+t^2) 确定y是x的函数,求dy/dx.
=ln(1+t^2),y=arctant 求d²y/dx²的时候d/dt*(dy/dx)=-(1/2
y=1/2·x·√(ln[x+²√(x²﹢a²)],求dy/dx及d²y/dx&
【急】求由参数方程组{x=ln根号(1+t^2),y=arctant所确定函数的一阶导数dy/dx和二阶导数d^2y/d
设参数方程x=t-In(1+t^2) y=arctant 确定函数y=y(x),求d^2y/dx^2