lim x->0+ x/(1-cosx)^1/2 答案为什么是2
lim x->0+ x/(1-cosx)^1/2 答案为什么是2
lim(e^(x^2)-1)/(cosx-1) ,x→0的极限为什么是-2
1.lim ([x]-|x|)x->1-2.lim (1-cosx)/xx->派/3这道题的答案是3/(2派)
lim x->pi (x^2-1)/cosx
lim(x→0)(cosx)^(1/ln(1+x^2))
求极限 x 趋于0 lim(cosx)^1/(x^2)
lim(x→0)(ln(1+x^2)/(sec-cosx))
lim[ln(1+x^2)]/(secx-cosx) x->0
lim(x趋向于0)(1-cosx)/x^2
lim(cosx/cos2x)^(x^1/2)求详细过程,答案是e^3/2
求lim(1-cosx)/x^2
lim(x->0)[cosx-e^(-x^2/2)]/[x^2[x+ln(1-x)]]