化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
[2sin50°+sin10°(1+根号3tan10°)]乘sin10°等于?
化简[2sin50°+sin10°(1+√3tan10°)] √(sin²80°)尽量简单点
化简[2sin50°+sin10°(1+3tan10°)]1+cos20°
化简:[2sin50°+sin10°(1+根号3*tan10°)]*根号sin^280°
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
2sin50 +sin10×(1+ √3tan10)