2sin50 +sin10×(1+ √3tan10)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 17:26:46
2sin50 +sin10×(1+ √3tan10)
2sin50° +sin10°×(1+ √3tan10°)
=2sin(60°-10°)+sin10°+√3tan10°sin10°
=2sin60°cos10°-2cos60°sin10°+sin10°+√3tan10°sin10°
=√3cos10°-sin10°+sin10°+√3tan10°sin10°
=√3cos10°+√3tan10°sin10°
=√3cos10°+√3(sin10°/cos10°)sin10°
=√3/cos10° (cos²10°+sin²10°)
=√3sec10°
=2sin(60°-10°)+sin10°+√3tan10°sin10°
=2sin60°cos10°-2cos60°sin10°+sin10°+√3tan10°sin10°
=√3cos10°-sin10°+sin10°+√3tan10°sin10°
=√3cos10°+√3tan10°sin10°
=√3cos10°+√3(sin10°/cos10°)sin10°
=√3/cos10° (cos²10°+sin²10°)
=√3sec10°
2sin50 +sin10×(1+ √3tan10)
求值:[2sin50°+sin10°(1+√3tan10°)]×√2sin80°
[2sin50+sin10(1+根号3tan10)]sin80
求值[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80°)
求值:[2sin50°+sin10°(1+√3tan10°)]√(1-sin^2 10°)
[2sin50°+sin10°(1+√3tan10°)]*√2(sin80°)*(sin80度)
化简[2sin50°+sin10°(1+√3tan10°)] √(2sin280°)
[2sin50°+sin10°(1+√3tan10°)]•√(sin²80°)
求[2sin50°+sin10°(1+√3tan10°0]sin80°的值
【跪求】【求值】(sin50(1+根号(3)*tan10)-cos20)\(根号(2)*cos80*sin10)
化简:[2sin50°+sin10°(1+根号3*tan10°)]*根号sin^280°
求【2sin50度+sin10度(1+根号3tan10度)】sin80度的值