An={n (1
an-an-1=2(n-1)
若数列an=(1+1/n)^n,求证an
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
An=1/(n+1)+1/(n+2)+.+1/2n,则An+1-An等于?
已知数列{an}满足an+1=2an+n+1(n∈N*).
数列{an}中,an+1+an=3n-54(n∈N*).
数列an中,(n+1)an+1-nan方+an+1an=0,求an
已知数列{an}中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2),求an
An=C(1,n)a1+C(2,n)a2+…C(n,n)an,
在数列{An}中,已知An+A(n+1)=2n (n∈N*)