lim x→0(1+2cosx)^secx

lim[ln(1+x^2)]/(secx-cosx) x->0 求极限lim x→π(sin3x)/(x-π)和求极限lim x→π/2(1+cosx)secx 1、lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx 求 lim ln(1+x+2x^2)+ln(1-x+x^2)/secx-cosx lim(x趋于0时)secx - 1/x^2 , limx趋向0[ln(1+x^2)/secx-cosx] lim下标x到二分之派,然后（1加cosx)3secx次幂求极限 lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x→0)(ln(1+x^2)/(sec-cosx)) 求Lim(x→0)(sinx/x)^(cosx/1-cosx) lim x→0 1-cosx/xsinx lim(x→0)(1/cosx)=?