An=1 A(n+1)=0.5(An+2/An) 求An的极限
在数列{an}中,an=1/n(n+1)(n+2),求Sn的极限
关于数列极限的已知数列an满足a1=0 a2=1 an=(an-1+an-2)/2 求lim(n->无穷)an
a1=1/2,an+1=an/an+2,求n/an的sn
1/an-an=2√n 且an>0 求an的通项公式
已知数列an满足1/a-an=2根号n,且an>0.求an的通项公式
数列极限的运算lim an/(an+1) =2 求lim 2anlim (2n+1)*an=3 求lim n*an
求2an+1-an=n+2的an通项,a1=0.5
已知a>0.数列{an}满足a1=a,an+1=a+ 1/an,(n=1,2…..),an极限存在,an>0.
设数列{an}中,a1=2,a(n+1)=an+n+1,求an
an=0,an+a(n+1)=2^n,求an通项
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
求证明一道极限的题An>1,An+1=An+1/An 求证An趋向正无穷