设数列{an}中,a1=2,a(n+1)=an+n+1,求an

设数列{an}中,a1=2,a(n+1)=an+n+1,求an 设数列{an}中,a1=2,an+1=an+n+1,则通项an=? 在数列{an}中,a1=1,an+1=(1+1/n)an+(n+1)/(2^n) (1) 设bn=an/n,求数列{bn 设数列｛an｝中,a1=1且(2n+1)an=(2n-3)a(n-1),(n大于等于2）,求{an},sn 数列an中 a1=1 a(n+1)=2an\(an+2) 求数列通项公式an 设数列{an},a1=2,a（n+1）=an+In·（1+1/n）,求an 数列{an}中,a1=35,an+1-an=2n-1,求an 数列{an}中,a1=2,a(n+1)=an(n+1)/n,求{an}通项式 已知数列{An}中,A1=1,A(n+1)=An/(1+2An),求An 数列{an}中,a1=1,且a(n+1)=2an+1.设bn=an+1 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 1．数列（an)中,a1=1,a(n+1)=an+2n,求an