(x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/22 01:55:47

(x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =19/6
化成(x² +x+1)/(x² +1)+(x² +1)/(x² +x+1)=13/6
急嗷

(x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =19/6
(x² +x+1)/(x² +1)+((x²+x+1)+(x² +1))/(x² +x+1) =19/6
(x² +x+1)/(x² +1)+1+(x² +1)/(x² +x+1) =19/6
(x² +x+1)/(x² +1)+(x² +1)/(x² +x+1)=13/6

2(x²-1²) 1-x²+2xy-y² 计算:(1).(-2xy²)*(3x²y)² 化简~(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x) （1)(x²-2x)²+2（x²-2x）+1 分解因式(2X²-3X+1)²-22X²+33X-1 因式分解：(2x²-3x+1)²-22x²+33x-1 （x²-2x）²+2x²-4x+1 ① X²+X-1+0,则2X³+3X²-X= 计算：[（x²-2x+1）/（x²-1）]÷[（x-1）(x²+x)]-x 1 f(x)=（1+x²)/(1-x²) 7/x²+x+3/x²-x=6/x²-1