已知数列{an}满足,a1=5,a
已知数列{an}满足条件:a1=5,an=a1+a2+...a(n-1) n大于等于2,求数列{an}的通项公式
已知数列{an}满足a1=100,an+1-an=2n,则a
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an
已知数列{an}满足a1=1,a2=a(a>0),数列{bn}=an*an+
已知数列{an}满足a1=2,a(n+1)=(5an-13)/(3an-7)则数列{an}的前100项的和是
已知数列{an}满足a1=4/3,2-a(n+1)=12/an+6
【高中数学题】已知数列{an}满足a1=1,a(n+1)=3an+1
已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式
已知数列{an},如果数列{bn}满足b1=a1,bn=an+a(n-1)则称数列{bn}是数列{an}的生成数列
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列{an}满足a1=1;an=a1+2a2+3a3+...+(n-1)a(n-1);
已知数列{An}满足A1=1,A=3(n-1)+A(n>/2)