求满足Y的平方加2x的四次方加一等于4x 的平方y
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x²-4x+y²-10y+29=0(x-2)²+(y-5)²=0(x-2)²=0(y-5)²=0x=2y=5x²y³+2
X²+2X-1=0两边同时除以x得x+2-1/x=0x-1/x=-2两边同时平方得x²+1/x²=6两边同时平方得x4+1/x4=34
3-√5先求出x^2的值(x^4-1)+x^2+2x=(x^2+1)(x^2-1)+x^2+2x这样就好解多了
x²+3x+1=0除以x得x+3+1/x=0x+1/x=-3∴(x+1/x)²=x²+2+1/x²=9即x²+1/x²=9-2=7∴﹙x
x^2-4x+y^2-10y+29=0x^2-4x+4+y^2-10y+25=0(x-2)^2+(y-5)^2=0x=2,y=5x^2y^2+2x^3*y^2+x^4y^2=x^2y^2(1+2x+x
(x+y)²=162xy=6,xy=3x²y²=92x²y²=18x的四次方加y的四次方=(x²+y²)²-2x&sup
/>x的四次方加2x的三次方加x的平方加1加2乘(x加x的平方)=x^4+2x^3+x^2+1+2(x+x^2)=x^4+2x^3+x^2+1+2x+2x^2=x^4+2x^3+3x^2+2x+1=x
解题思路:本题主要先化成完全平方公式形式再进行解答解题过程:
X2+Y2-4X-6Y+13=0X2-4X+4+Y2-6Y+9=0(X2-4X+4)+(Y2-6Y+9)=0(x-2)2 +(y-3)2=0所以,x-2=0 x=2y-
x²+2xy+4y²+x²y²+1=8xy(x²-4xy+4y²)+(x²y²-2xy+1)=0(x-2y)²
由已知可得:y^4+2x^4-4x^2y+1=0所以y^4-2y^2+1+2(x^4-2x^2y+y^2)=0(y^2-1)^2+2(x^2-y)^2=0从而y^2=1并且x^2=yy=1时,x=1或
x方+y方+5/4=2x+y(x方-2x+1)+(y方-y+1/4)=0(x-1)方+(y-1/2)方=0x=1,y=1/2xy/(x+y)=1/3
先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+
1/(x^4)+4/(y^4)xy=1,所以y=1/x即y^4=1/(x^4)代入原式,得到1/(x^4)+4(x^4)再由重要不等式,得到1/(x^4)+4(x^4)≥2(根号)1/(x^4)·4(
x²-4x+1=0两边同时除以xx-4+1/x=0x+1/x=4两边同时平方x²+2+1/x²=16x²+1/x²=14两边同时平方x^4+2+1/x
x^2/(x^4+1)=33x^4+3=x^2两边平方9x^8+18x^4+9=x^4两边减去9x^49x^8+9x^4+9=-8x^4所以x^4/(x^8+x^4+1)=-9/8再问:标准答案是:1
x^4+y^4=x^4+2x^2y^2+y^4-2x^2y^2=(x^2+y^2)^2-2x^2y^2=(x^2+y^2+√2*xy)(x^2+y^2-√2*xy)
6X的四次方减11
方法一:x^4+y^4+(x+y)^4=(x^4+2x^2y^2+y^4)-2x^2y^2+(x^2+2xy+y^2)^2=[(x^2+y^2)^2-(xy)^2]+[(x^2+y^2+2xy)^2-
X四次方+X²Y²+X²Y²-X²Y²+Y四次方=(X²+Y²)²-X²Y²