不等式sinx 根号3cos
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这样的吧:0.25=1/4f(x)=3√2sin0.25xcos0.25x+√6cos²0.25x-√6/2-m≤03√2/2sin0.5x+√6/2(cos0.5x+1)-√6/2-m≤0
sin^3X+cos^3X=(sinx+cosx)(sin^2x-sinxcosx+cos^2x)=根号2(1+sinxcosx)sinX+cosX=根号2所以sin^2x+cos^2x+2sinxc
已知:函数f(x)=2sinxcosx+2√3cos²x-√3求:(1)单调增区间和最小正周期;(2)当x∈[-π/4,π/4]时求最值.f(x)=2sinxcosx+2√3cos²
因为cos2x=2cos^2x-1;sin2x=2(sinx)(cosx)所以f(x)=cos^2x+(根号3)sinx*cosx=(cos2x+1)/2+[(根号3)(sin2x)]/2因为1/2=
因为cos2x=2cos^2x-1;sin2x=2(sinx)(cosx)所以f(x)=cos^2x+(根号3)sinx*cosx=(cos2x+1)/2+[(根号3)(sin2x)]/2因为1/2=
√3sinx-cosx+2cos(x-π/6)=2sin(x-π/6)+2cos(x-π/6)=2√2sin[(x-π/6)+π/4]=2√2sin(x+π/12)
1.f(x)=sinx/3cosx/3+根号3cos^2x/3=1/2sin2x/3+根号3/2(cos2x/3+1)=sin(2x/3+pi/3)+根号3/2对称中心的横坐标满足sin(2x/3+p
cosx+根号3sinx=2*[1/2cosx+(根号3)/2sinx]=2*【sinπ/3*2cosx+cosπ/3*sinx】=2cos(x-π/3)希望我的答案您能满意,
f(x)=3√2sinx/4cosx/4+√6cos²x/4-√6/2-m=3√2/2sin(x/2)+√6/2(1+cosx/2)-√6/2-m=3√2/2*sin(x/2)+√6/2*c
[sinx+cos(π+x)]/[sinx+sin(π/2-x)]=(sinx-cosx)/(sinx+cosx)=(tanx-1)/(tanx+1)=1-[2/(tanx+1)]sinx=√3/3∴
先证cos(cosx)>cosx再证cosx>sin(sinx)详细如下建立坐标系,设cosX=t,以坐标原点为圆心作一标准圆,则Sin(cosX)=Sint,t为x轴的正方向和一条射线的夹角Sint
f(x)=1/2sinx/2+√3/2(1+cosx/2)=1/2sinx/2+√3/2cosx/2+√3/2=sin(x/2+π/6)+√3/2
答:利用公式:(sinx)^2+(cosx)^2=1cos2x=2(cosx)^2-1=1-2(sinx)^2sin2x=2sinxcosxsin(a+b)=sinacosb+cosasinbf(x)
y'=-sin√x*(√x)'+1/(2√sinx)*sinx'=-sin√x/[2(√x)]+1/(2√sinx)*cosx
y=cosx-√3sinx=2(1/2cosx-√3/2sinx)=2(cosxcosπ/3-sinxsinπ/3)=2cos(x+π/3)再问:那也可以化成2sin(x-π/6)吗再答:y=cosx
=-sinx/(1-cosx)*√[(1/cosx-1)/(1/cosx+1)]]=-sinx/(1-cosx)*[(1-cosx)/|sinx|]sinx>0=-1sinx再问:化简,不用求值再答:
cos(x-180)*sin(x-180)=1/2sin(2x-360)=1/2sin2x又因为√1-sinx+√1+sinx=√3两边平方1-sinx+1+sinx+2√(1-sin2x)=3解得: