作业帮高数,极限问题,求大神解答...
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/04 13:17:13
高数,极限问题,求大神解答...
求解.
∵x→0时,1-cosx~x²/2
∴1-cos√x x/2
lim [1- √(cosx) ] / [x(1- cos√x )]
= lim [1- √(cosx)] / (x²/2)
= lim [1-√(cosx)][1+√cosx] / (x²/2)[1+√cosx]
= lim (1- cosx) / (x²/2)(1+√cosx) ...展开全文你好!
∵x→0时,1-cosx~x²/2
∴1-cos√x x/2
lim [1- √(cosx) ] / [x(1- cos√x )]
= lim [1- √(cosx)] / (x²/2)
= lim [1-√(cosx)][1+√cosx] / (x²/2)[1+√cosx]
= lim (1- cosx) / (x²/2)(1+√cosx)
= lim (x²/2) / (x²/2)(1+√cosx)
= 1/2收起
∴1-cos√x x/2
lim [1- √(cosx) ] / [x(1- cos√x )]
= lim [1- √(cosx)] / (x²/2)
= lim [1-√(cosx)][1+√cosx] / (x²/2)[1+√cosx]
= lim (1- cosx) / (x²/2)(1+√cosx) ...展开全文你好!
∵x→0时,1-cosx~x²/2
∴1-cos√x x/2
lim [1- √(cosx) ] / [x(1- cos√x )]
= lim [1- √(cosx)] / (x²/2)
= lim [1-√(cosx)][1+√cosx] / (x²/2)[1+√cosx]
= lim (1- cosx) / (x²/2)(1+√cosx)
= lim (x²/2) / (x²/2)(1+√cosx)
= 1/2收起