(1)-2x2y(3xy2z-2y2z);
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(1)-2x2y(3xy2z-2y2z);
(2)(2ab)2•(a2-b2)-(2a2b2)2÷(4b2)+4a2b4;
(3)1232-124×122;
(4)(
-y)
(2)(2ab)2•(a2-b2)-(2a2b2)2÷(4b2)+4a2b4;
(3)1232-124×122;
(4)(
x |
2 |
(1)原式=-6x3y3z+4x2y3z;
(2)原式=4a4b2-4a2b4-4a4b4÷4b2+4a2b4=3a4b2;
(3)原式=1232-(123+1)×(123-1)=1232-(1232-1)=1232-1232+1=1;
(4)原式=
1
4x2-xy+y2-
1
4x2+
1
4y2=-xy+
5
4y2;
(5)原式=(4a2+4ab+b2-b2-4ab-8a)÷(-
1
2a)=(4a2-8a)÷(-
1
2a)=-8a+16.
(2)原式=4a4b2-4a2b4-4a4b4÷4b2+4a2b4=3a4b2;
(3)原式=1232-(123+1)×(123-1)=1232-(1232-1)=1232-1232+1=1;
(4)原式=
1
4x2-xy+y2-
1
4x2+
1
4y2=-xy+
5
4y2;
(5)原式=(4a2+4ab+b2-b2-4ab-8a)÷(-
1
2a)=(4a2-8a)÷(-
1
2a)=-8a+16.
(1)-2x2y(3xy2z-2y2z);
4x2y-{x2y-「3xy2 – 1/ 2(4x2y-8xy2)+x2y」}-5xy2
化简求值:2(x2y+xy)-3(x2y-xy)-4x2y,其中x=-1,y=1.
2(x2y+xy)-3(x2y+xy)-4x2y其中x=-2,y=12
先化简,再求值(3x2y-2xy2)-(xy2-2x2y),其中x=-1,y=2.
先化简后求值:4x2y-[6xy-3(4xy-2)-x2y]+1,其中x=2,y=-12
(x3-2y3-3x2y)-(3x3-3y3-7x2y)
一个多项式加上x2y-3xy2得2x2y-xy2,则这个多项式是( )
化简求值①化简:4ab+8-2b2-9ab-6②先化简,再求值:已知3x2y-[2x2y-3(2xy-x2y)-xy],
(X+Y)2=1402X2Y*3=14400
(2x2y-2xy2)-[(-3x2y2+3x2y)+(3x2y2-3xy2)],其中x=-1,y=2.
有这样一道题:“计算(2x3-3x2y-2xy2)-(x3-2xy2+y3)+(-x3+3x2y-y3)的值,其中x=1