1*2*3*4*.*(n-1)=?
证明:1+2C(n,1)+4C(n,2)+...+2^nC(n,n)=3^n .(n∈N+)
Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
急1)C(n,0)+2C(n,1)+3C(n,2)+4C(n,3) +...+(n+1)C(n,n)=(n+2)*2^(
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
1 + (n + 1) + n*(n + 1) + n*n + (n + 1) + 1 = 2n^2 + 3n + 3
已知递推公式f(n)=(n-1)(n-2)[f(n-2)+f(n-3)+(n-3)*f(n-4)] (n>4)求通项公式
化简:1/(n+1)(n+2)+1/(n+2)(n+3)+1/(n+3)(n+4)
(n+1)(n+2)/1 +(n+2)(n+3)/1 +(n+3)(n+4)/1
证明(1+2/n)^n>5-2/n(n属于N+,n>=3)
证明当自然数n>=4时,n^3>3n^2+3n+1
用数学裂项法证明:1/1*2*3+1/2*3*4+...+1/N(N+1)(N+2)=N(N+3)/4(N+1)(N+2
用数学归纳法证明:1/1*2*3+1/2*3*4+...+1/N(N+1)(N+2)=N(N+3)/4(N+1)(N+2