与数列和归纳法有关设an=1+1/2+1/3+...+1/n,g(n)=[a1+a2+a3+...+a(n-1)]/(a
与数列和归纳法有关设an=1+1/2+1/3+...+1/n,g(n)=[a1+a2+a3+...+a(n-1)]/(a
已知数列an=a(n-1)+a(n-2)+a(n-3).a1=1,a2=2,a3=3 用数学归纳法证明 an
设数列{an}满足a1+3a2+3^2a3+.3^n-1×an=n/3,a∈N+.
设数列{An}满足A1+3A2+3^2*A3+...+3^(n-1)*An=n/3,a属于正整数.
设数列{an}满足a1+2a2+3a3+.+nan=n(n+1)(n+2)
数列证明题:设数列{an}满足:A(n)=a1+a2+~+an,B(n)=a2+a3+~+a(n+1),C(n)=a3+
设数列{an}满足a1+3 a2+3^2 a3+……+3^n-1 an=n/3,a属于N* 求数列{an}的通项
已知数列{an}满足a1=1;an=a1+2a2+3a3+...+(n-1)a(n-1);
整数数列{An}满足 A1*A2+A2*A3+…+A(n-1)*An=(n-1)*n*(n+1)/3 ,(n=2,3,…
已知数列{an}满足a1=1,an=a1 +1/2a2 +1/3a3 … +1/(n-1)a(n-1),(n>1,n∈N
已知数列{an}中满足a1=1,a(n+1)=2an+1 (n∈N*),证明a1/a2+a2/a3+…+an/a(n+1
设数列{an}的前n项和为Sn,并且满足2Sn=an²+n,an>0.(1)求a1,a2,a3.(2)猜想{a