x3(y-z)+y3(z-x)+z3(x-y)
x3(y-z)+y3(z-x)+z3(x-y)
不等式选讲设x,y,z为正数,证明:2(x3+y3+z3)≥x2(y+z)+y2(x+z)+z2(x+y).
因式分解(x+y+z)3-x3-y3-z3
因式分解X2(Y+Z)+Y2(Z+X)+Z2(X+Y)-(X3+Y3+Z3)-2XYZ
x3+y3+z3+(x+y)3+(y+z)3+(z+x)3因式分解
已知x3+y3-z3=96,xyz=4,x2+y2+z2-xy+xz+yz=12,则x+y-z=( )
(x加y加z)3次方--x3次方-y3次方-z3次方.
已知X+Y+Z=0,求X3次方+Y3次方+Z3次方等于多少?
已知x+y+z=2,x2+y2+z2=12则x3+y3+z3=
若x,y,z大于等于0,求证:x3+y3+z3大于等于3xyz
已知x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,求xy(x+y)+yz(y+z)+zx(z+x)的值
已知x+y+z=3,x2+y2+z2=19,x3+y3+z3=30则xyz=?