幼儿算数find a number whose half exceeds its third by the sum of

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幼儿算数find a number whose half exceeds its third by the sum of its digits
具体什么题意我没弄懂,请给列出具体公式步骤,谢啦

求一个数,这个数字的一半减去它的三分之一正好是它的各位数字之和.
设为x, 那么x/2-x/3 = x/6
x/6正好是个位数字之和.
如果这个数字是1位数,那么x/6=x, 那么这个数是0, 符合要求
如果是两位数,设x=ab,也就是10a+b, 10a+b=6(a+b), 4a=5b, a=5,b=4, 也就是说x=54符合要求
更多位数以此类推,不过幼儿园算数不会上千上万的吧?

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