计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
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计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
1 (log4 3+log8 3)log3 2
=(lg3/lg4+lg3/lg8)*(lg2/lg3)
=lg3*(1/lg4+1/lg8)*(lg2/lg3)
=(1/lg4+1/lg8)*lg2
=lg2/lg4+lg2/lg8
=lg2/(2*lg2)+lg2/(3*lg2)
=1/2+1/3
=5/6
2 loga b×logb c×logc a
=(lgb/lga)*(lgc/lgb)*(lga/lgc)
=(lgb/lga)*(lgc/lgb)*(lga/lgc)
=1
=(lg3/lg4+lg3/lg8)*(lg2/lg3)
=lg3*(1/lg4+1/lg8)*(lg2/lg3)
=(1/lg4+1/lg8)*lg2
=lg2/lg4+lg2/lg8
=lg2/(2*lg2)+lg2/(3*lg2)
=1/2+1/3
=5/6
2 loga b×logb c×logc a
=(lgb/lga)*(lgc/lgb)*(lga/lgc)
=(lgb/lga)*(lgc/lgb)*(lga/lgc)
=1
计算:1 (log4 3+log8 3)log3 2 2 loga b×logb c×logc a
数学题目 对数函数计算:log2 25×log3 4×log5 9=证明:loga b×logb c ×logc a=1
利用换底公式证明Loga b*logb c*logc a=1
(log4(3)+log8(3))*log3(2)
(log4 3+log8 3)*(log3 2+log4 2)
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4^3+log8^3)(log3^2+log9^2)
求值(log4(3)+log8(3))×(log3(2)+log9(2))
求值(log3(2)+log9(2))*(log4(3)+log8(3))
(log3 2+log9 2)*(log4 3+log8 3)求值
(log3^2 + log9^4)×(log4^3 + log8^3)
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)