函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值
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函数f(x)=cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x的最小值
A.0 B.2 C.9/4 D.3
A.0 B.2 C.9/4 D.3
cos2x+cos(x+π/3)+sin(x+π/6)+3sin^2x
=cos2x+1/2*cosx-根号3/2*sina+根号3/2*sinx+1/2*cosx+3sin^2x
=cos2x+cosx+3sin^2x
=1-2sin^2x+cosx+3sin^2x
=1+sin^2x+cosx
=-cosx^2+cosx+2
=-(cosx-1/2)^2+9/4
当cosx=-1时,
所取得值最小为0
=cos2x+1/2*cosx-根号3/2*sina+根号3/2*sinx+1/2*cosx+3sin^2x
=cos2x+cosx+3sin^2x
=1-2sin^2x+cosx+3sin^2x
=1+sin^2x+cosx
=-cosx^2+cosx+2
=-(cosx-1/2)^2+9/4
当cosx=-1时,
所取得值最小为0
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