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数列求和.已知an=(0.5)^n,设bn/an=(2n+5)/((2n+1)(2n+3)),求bn的前n项和.

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数列求和.已知an=(0.5)^n,设bn/an=(2n+5)/((2n+1)(2n+3)),求bn的前n项和.
n/an = (2n+5)/[(2n+1)(2n+3)]
= 2/(2n+1) - 1/(2n+3)
bn =[2/(2n+1) - 1/(2n+3)] (0.5)^n
Sn = b1+b2+..+bn
= [( 1/3 -1/10)+ (1/10-1/28)+(1/28-1/72)+.( 2/(2n+1)(0.5)^n - 1/[2^n(2n+3)]) ]
= 1/3 - 1/[2^n(2n+3)]