求根号2/4sin(π/4-x)+根号6/4cos(π/4-x)的化简,

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/03 01:13:45

根号2/4sin(π/4-x)+根号6/4cos(π/4-x)
=(根号2)/2 *[1/2 *sin(π/4-x) + (根号3)/2 *cos(π/4-x)]
=(根号2)/2 *[sin(π/4-x)*cos(π/3) + cos(π/4-x)*sin(π/3)]
=(根号2)/2 *[sin(π/4 -x +π/3)]
=(根号2)/2 *[sin(7π/12 -x)]
=(根号2)/2 *[sin(π - 5π/12 -x)]
=(根号2)/2 *sin(x+ 5π/12)
再问：那请问一下 (根号3)/2是哪来的啊，谢谢啦，我不太懂
再答：根号6/4=根号2/2 * 根号3/2

求根号2/4sin(π/4-x)+根号6/4cos(π/4-x)的化简, 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 求f(x)=2sin^2(π/4-x)-2倍根号3cos^2x+根号3的最小正周期和单调递减区间求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3 f(x)=sin平方x+2根号3sin(x+π/4)cos(x-π/4)-cos平方x-根号3 根号下(sin""x+4cos"x)-根号下(cos""x+4sin"x)=? 已知sin(x/2)-2cos(x/2)=0,求tanx的值,求cos2x除以根号2*cos(π/4+x)*sinx的值根号2/4sin（π/4-x）+根号6/4cos（π/4-x）化简已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x f(x)=2sin^2(π/4-x)-2根号3cos^2x+根号3如题 f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3 求函数f(x)=5根号3cos^2x 根号3sin^2x-4sinxcosx(兀/4