化简:(3c-y)^2-(2c+y)^2-5c(c-y)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/04/28 14:48:08
化简:(3c-y)^2-(2c+y)^2-5c(c-y)
标题和这一条化简(解释):[(2C-2分之3×y-(C-y)]^2-2分之3×Cy
标题和这一条化简(解释):[(2C-2分之3×y-(C-y)]^2-2分之3×Cy
(3c-y)^2-(2c+y)^2-5c(c-y)=(9c^2-6cy+y^2)-(4c^2+4cy+y^2)-5c^2+5cy
=9c^2-6cy+y^2-4c^2-4cy-y^2-5c^2+5cy
=-5cy
[(2C-2分之3×y-(C-y)]^2-2分之3×Cy = (2c-3/2y-c+y)^2-3/2cy
=(c-1/2y)^2-3/2cy
=c^2-cy+1/4y^2-3/2cy
=c^2-5/2cy+1/4y^2
=9c^2-6cy+y^2-4c^2-4cy-y^2-5c^2+5cy
=-5cy
[(2C-2分之3×y-(C-y)]^2-2分之3×Cy = (2c-3/2y-c+y)^2-3/2cy
=(c-1/2y)^2-3/2cy
=c^2-cy+1/4y^2-3/2cy
=c^2-5/2cy+1/4y^2
化简:(3c-y)^2-(2c+y)^2-5c(c-y)
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