{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
计算:(1)2/(x+y)+4y/x²-y²(2)x²/x+y-x+y
因式分解x²(x-2y)+y²(2y-x)
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
{(x+2y)²—(x-2y)²-(x+2y)(x-2y)-4y²}÷2x求
x(x-y)-y(y-x)+(x-y)²因式分解
{(x-y)²+(x+y)(x-y)}÷2x
(x-2y)²+(2x-4y)(x+y)+(x+y)²
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
[(2x+y)²-y(y+4x)-8x] ÷2x 其中x=2,y=-1
(x-y)的四次方(x-y)-2(x-y)²(y-x)³等于?
(2x+y)²-y(y+4x)-8x等于?