2X-5Y=10 2X-Y=14 求XY
如果x^2+xy+y-14,y^@+xy+x=28,求x+y的值.
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
2X-5Y=10 2X-Y=14 求XY
若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值
已知xy/x+y=3,求代数式2x-5xy+2y/x-3xy+y
已知xy/x+y=2,求代数式3x-5xy+3y/-x+2xy-y的值
已知xy=2(x+y),求(5x-xy+5y)/(3xy-x-y)的值
已知x-y=2xy,求代数式3x-5xy-3y/x+xy-y的值
已知X+Y=2XY,求4X-5XY+4Y 除以X+XY+Y 的值
已知X+Y分之XY=2,求-X+3XY-Y分之3X+5XY+3Y
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+2(xy+y)的值