{x+y+z=4 {2y+z=0 {3x+2y-4z=-1
1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.
{x+y+z=4 {2y+z=0 {3x+2y-4z=-1
若x-2y+4z=1,x+3y-7z=0,则y:z=?
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x+y+z=2 4x+2y+z=4 2x+3y+z=1
x+y+z=4 x-2y+z=-2 x+2y+3z=0求解
x-3y+z=0,3x-2y-4z=0,则x:y:z=多少?
x^2+y^2+z^2+4x+4y+4z+1=0,求x+y+z
x^2+y^2+z^2+4x+4y+4z+1=0求x+y+z
x^2+y^2+z^2+4x+4y+4z+1=0 求x+y+z
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
x+2y-4z=0 3x+y-z=0,则x:y:z=