x+y+z=4 x-2y+z=-2 x+2y+3z=0求解
x+y+z=4 x-2y+z=-2 x+2y+3z=0求解
求解三元一次方程组:{x+y/2=y+z/3=z+x/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
三元一次方程求解:①x+2z=3,2x+y=2,2y+z=7.②x+y+z=2,3x-y-4z=5,2x+3y-2z=0
2x+3y+z=11,3x+y-z=2,x+y+z=6求解
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x/2=y/3=z/5 x+3y-z/x-3y+z
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
x-3y+z=0,3x-2y-4z=0,则x:y:z=多少?
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
x+2y-4z=0 3x+y-z=0,则x:y:z=