f(x)=4sin(2x+π/3)怎么变成4cos(2x-π/6)
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+/4π) 三角函数
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
已知函数f(x)=sin^2*x-根号3*sinπ/4*x*cosπ/4*x
f(x)=2SIN^2(x+π\4)-cos(2x+π\6) 化简 谢
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
已知函数f(x)=2sin(x/4)cos(x/4)-2√3sin²(x/4)+√3,且g(x)=f(x+π/
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
求化简f(x)=sin^2x+2根号3sin(x+π/4)cos(x-π/4)-cos^2x-根号3