证明(tan^2a+tana+1)(cot^2a+cota+1)=tan^2a+cot^2a+1

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/12 18:14:13

(tan^2a+tana+1)(cot^2a+cota+1)中应该是
(tan^2a+tana+1)(cot^2a-cota+1)=tan^2a+cot^2a+1
tan^2a+cot^2a+1
=tan^2a+1/tan^2a+1
=(tana+1/tana)^2-1
=(tana+1/tana+1)(tana+1/tana-1)
=(tan^2a+tana+1))[(tana+1/tana-1)/tana]
=(tan^2a+tana+1)(1+1/tan^2a-1/tana)
=(tan^2a+tana+1)(cot^2a-cota+1)

证明(tan^2a+tana+1)(cot^2a+cota+1)=tan^2a+cot^2a+1 求证(1+tan^2A)/(1+cot^2A)=(1-tanA/1-cotA)^2 证明：(1+tan a+cot a)/(1+tan^2 a+tan a)-cot a/(1+ tan^2 a)=sin 已知∠A为锐角,tanA-cotA=4,tan^2A+cot^2A=? 若tana+cota=a则tan^2a+cot^2a= 如何证明cot(1/2A)-tan(1/2A)=2cot(A) 若tana-cota=2,则tan^2a+cot^2a= 已知tana+cota=3,则tan^2a+cot^2a=? 若tana-cota=2,则tan^2+cot^2a= 已知tana+cota=9/4,则tan^2a+secacsca+cot^2的值怎么证明tan^2A+cot^2A不等于1 证明下列各式:(1+tana+cota)/(1+tan^2 a+tana)-cota/(1+tan^2 a)=sinac