化简2sin[(π/2)+α]-cos(-π+α)/cos(3π+aα)
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-
化简:sinα-√3 cosα+2cos(α-π/3)
已知向量a=(sinα+cosα,√2sinα),b=(cosα-sinα,√2cosα),a∈[0,π/2],且
已知sin a=2cos a 计算⑴(sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)
化简sin(2π+a)cos(π-a)cos(π/2-a)cos(7π/2-a)/cos(π-a)sin(3π-a)si
已知(3sinα+cosα)/(3cosα-sinα)=2,则2-3sin(α-3π)sin(1.5π-α)-[cos(
化简 sin(2π-a)sin(π+a)cos-π-a) / sin(3π-a)cos(π-a)
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(
化简 (1+sinα+cosα)(sinα/2 -cosα/2) / 根号下 2+2cosα ,(3π/2