作业帮(1-1/2*2)(1-1/3*3)(1-1/4*4).(1-1/2010*2010)(1-1/2011*2011)
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/04/30 19:21:50
(1-1/2*2)(1-1/3*3)(1-1/4*4).(1-1/2010*2010)(1-1/2011*2011)
原式=(1^2-(1/2)^2)(1^2-(1/3)^2)(1^2-(1/4)^2)...(1^2-(1/2010)^2)(1^2-(1/2011)^2)
=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4)...(1+1/2010)(1-1/2010)(1+1/2011)(1-1/2011)
=(3/2)*(1/2)*(4/3)*(2/3)*(5/4)*(3/4)*...*(2011/2010)*(2009/2010)
=(1*2011)/(2*2010)
=2011/4020
=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4)...(1+1/2010)(1-1/2010)(1+1/2011)(1-1/2011)
=(3/2)*(1/2)*(4/3)*(2/3)*(5/4)*(3/4)*...*(2011/2010)*(2009/2010)
=(1*2011)/(2*2010)
=2011/4020
计算:(1/2-1)(1/3-1)(1/4-1)...(1/2010-1)(1/2011-1)(1/2012-1)
1/1×2+1/2×3+1/3×4+…+1/2010×2011+1/2012×2013
计算:|1/2-1|+|1/3-1/2|+|1/4-1/3|+...+|1/2011-1/2010|+丨12012-1/
(1/2011*1/2010*1/2009*...1/3*1/2*1)∧2011*(2011*2010*2009*...
当x=2,1/2,3,1/3,4,1/4,…,2010,1/2010,2011,1/2011,时,
(1+1/2+1/3+.+1/2010)×(1/2+1/3+.+1/2011)-(1+1/2+1/3+.+1/2011)
1/2+(1/3+2/3)+(1/4+2/4+3/4)+...+(1/2011+2/2011+...+2010/2011
1/1*2+1/2*3+1/3*4+……+1/2010*2011
1*2/1+2*3/1+3*4/1+…2010*2011/1等于?
(1/2012-1)(1/2011-1)(1/2010-1)...(1/3-1)(1/2-1)咋算
(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)
(1\2012-1)(1\2011-1)(1\2010-1)...(1\3-1)(1\2-1)=?