(2014•福建模拟)不等式sin2θ-(22+2a)sin(θ+π4)-22cos(θ−π4)>-3-2a对θ∈[0,
Θ∈(π/2,3π/4) sin2Θ∈a sinΘ+cosΘ
若2sin(π/4+a)=sinθ+cosθ,2sin^2β=sin2θ,求证sin2a+(1/2)cos2β=0
若2sin(π/4+a)=sinθ+cosθ,2sin^2β=sin2θ,求证sin2a+(1/2)cos2β=0.
若2sin(π4+α)=sin θ+cos θ,2sin2β=sin 2θ,求证:sin&
若2sin(π/4+θ)=sinθ+cosθ,2sin^2(β)=sin2θ,求证sin2α+1/2cos2β=0
2sin(π/4+a)=sinθ+cosθ,且2sin^2b=sin2θ,求sin2a+1/2cos2b
若sin(π/4+α)=sinθ+cosθ,2sin^2β=sin2θ,求证:sin2θ+2cos2β=3
(2013•湖北模拟)已知tanθ=2,则2sin2(θ−π4)−cos(π−2θ)1+cos2θ=( )
(2010•湖北模拟)设a=(1,2(sinx+cosx)),b=(1−2sin2(x+π4),cos(x+π4)),f
已知cosθ=-3/5,θ∈(π/2,π) 求2/sin2θ-cosθ/sinθ+tan^2(θ/2)+sin^4(θ/
设sin(π+α)=4/5,α∈(π/2,3π/2),则sin2α-【cos(a/2)】^2的值为----
若θ∈(π4,π2),sin2θ=116,则cosθ-sinθ的值是 ___ .