(1/2+1/3+…+1/2011)(1+1/2+…+1/2010)-(1+1/2+…+1/2011)(1/2+1/3+
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/12 18:31:53
(1/2+1/3+…+1/2011)(1+1/2+…+1/2010)-(1+1/2+…+1/2011)(1/2+1/3+…+1/2010)计算
别做错啦
别做错啦
(1/2+1/3+…+1/2011)(1+1/2+…+1/2010)
-(1+1/2+…+1/2011)(1/2+1/3+…+1/2010)
= [(1/2+1/3+…+1/2010) +1/2011] [1+ (1/2+…+1/2010)]
-[1+ (1/2+…+1/2010) + 1/2011](1/2+1/3+…+1/2010)
= 2012/2011(1/2+1/3+…+1/2010)+(1/2+1/3+…+1/2010)^2 + 1/2010(2011)
- 2012/2011(1/2+…+1/2010) - (1/2+…+1/2010)^2
= 1/2010(2011)
=1/4042110 #
-(1+1/2+…+1/2011)(1/2+1/3+…+1/2010)
= [(1/2+1/3+…+1/2010) +1/2011] [1+ (1/2+…+1/2010)]
-[1+ (1/2+…+1/2010) + 1/2011](1/2+1/3+…+1/2010)
= 2012/2011(1/2+1/3+…+1/2010)+(1/2+1/3+…+1/2010)^2 + 1/2010(2011)
- 2012/2011(1/2+…+1/2010) - (1/2+…+1/2010)^2
= 1/2010(2011)
=1/4042110 #
计算:(1-1/2)(1/3-1)(1-1/4)(1/5-1)……(1-1/2010)(1/2011-1)
(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)
(-2012)-(-2011)-(-2010)-……-(-1)-2-3-……-2011-2012=(?)
1/1*2+1/2*3+1/3*4+……+1/2010*2011
1+1\(1+2)+1\(1+2+3)+1\(1+2+3+4)+……1\(1+2+3+……2010)
(1-1/2)+(1/2-1/3)+(1/3+1/4)+……+(1/2010-1/2011)=?用简算方法,要过程
1/1×2+1/2×3+1/3×4+…+1/2010×2011+1/2012×2013
计算 (-1)+(+2)+(-3)+(+4)+(-5)+…+(-2010)+(+2011)
计算(1+3+5+……+2011)—(2+4+6+……+2010)
(1/2+1/3+……+1/1997)(1+1/2+……+1/1996)-(1+1/2+……+1/1997)(1/2+1
1、(1/2+1/3+……1/1007)*(1+1/2+……1/2006)-(1+1/2+……+1/2007)*(1/2
计算:(2011/1-1)(2010/1-1)(2009/1-1)…(3/1-1)(2/1-1)