设a1=3²-1²,a2=5²-3²…an=(2n+1)²-(2n-1
1²-2²+3²-4²+5²-6²+…-100²+
设数列an满足a1+3a2+3²a3……+3n-1次方an=n/3
设数列{An}满足A1+3A2+3²A3+******+3^(n-1)An=n/3
1.计算:1²+4²+6²+7²=102,2²+3²+5&s
(2²+4²+6²+.+98²+100²)-(1²+3&su
一到数学计算题已知:1²+2²+3²+...+n²=1/6n(n+1)(2n+1
设复数z=(a²-1)+(a²-3a+2)i,若z²
已知数列an中,a1=1,a2=0,对任意正整数n,m(n>m)满足(an)²-(am)²=(an-
已知方程x²+y²-2(m+3)+2(1-4m²)+(4m²)²+9=
已知(m-1)²+|6m+3n|=0,求(4m²-mn-6n²)-2(m²-3m
若数列{an}满足a1+3a2+3²a3+···+3^n-1an=n/2 则an=
一道初中计算题 已知1²+2²+3²+……=1/6n(n+1)(2n+1),试求2&sup