一道数学题：1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/16 22:07:11

/>原式=1/(x-1)+[1/(x-2)-1/(x-1)]+[1/(x-3)-1/(x-2)]……+[1/(x-100)-1/(x-99)]
=1/(x-1)-1/(x-1)+1/(x-2)-1/(x-2)+……+1/(x-99)-1/(x-99)+1/(x-100)
=0+0+……+1/(x-100)
=1/(x-100)

一道数学题：1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100) 1+x+x^2+x^3+.+x^99+x^100 x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) 数学题（x-1)(x-3)(x+4) 一道分式数学题、已知x^2+x-1=0、求x-[1-2/(1-x)]/（x+1)-[x(x^2-1)]/x^2-2x+1 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 分解公因式(1+X)+X(1+X)+X(1+X)^2+X(1+X)^3+...+X(1+X)^99 求一道数学题.先化简：（3/x+1-x+1)÷x^2-4x+4/x+1,然后从-1 一道高一函数数学题f(x)+2f(x+1/1-x)=3x,求f(x) 1X+2X+3X…+98X+99X+100X=50500X X等于多少? 1x+2x+3x+4x+5x+6x+7x…+99x=100