(2x-y)(-y+2y)(y+x)(y²+4)

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/26 03:13:51

(2x-y)(-y+2y)(y+x)(y²+4)
=(2x-y)(y)(y+x)(y²+4)
=y(2x-y)(x+y)(y²+4)
=y(2x²+xy-y²)(4+y²)
=y(8x²+4xy-4y²+2x²y²+xy^3-y^4)
=8x²y+4xy²-4y^3+2x²y^3+xy^4-y^5

(2x-y)²-4(x-y)(x+2y) 化简：（2x-y)²-4(x-y)(x+y) {(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y x^2-y^2/x+y-4x(x-y)+y^2/2x-y, （x-2y）²+（2x-4y)(x+y)+(x+y)² x+2y+4y^2/x-y+4x^y/4y^2-x^2 (2x-y)^2-4(x-y)(x+2y) 已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y² x+2y+4x^2y/4y^2+4y^2/x-2y 4x(y-x)-y^2因式分解 (x+3y-4)(2x-y) [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y