cos2x+cosx=0,则sin2x+sinx
cos2x+cosx=0,则sin2x+sinx
sinx+2cosx=0,则sin2x+cos2x=
sinx×cos2x-sin2x×cosx
若3SinX=CosX,则Cos2X+Sin2X等于?
cos2x+cosx=0 求sin2x+sinx的值
已知1+sinx+cosx+sin2x+cos2x=0,求tanx
解方程 sin2x/sinx=cos2x/cosx
怎么证明cos2x/1-sin2x = cosx+sinx/cosx-sinx
求证:(1-2sinx×cosx)/cos2x-sin2x=(cos2x-sin2x)/(1+2sinx×cosx)
设(2cosx-sinx)(sinx+cos2x+3)=0,则2cos^2x+sin2x/1+tanx=?
已知2sin2x-cos2x+sinxcosx-6sinx+3cosx=0,求2cosx(sinx+cosx)1+tan
已知sinx=-1/2cosx,cosx-sinx/cosx+sinx+sin2x+cos2x的值