cos2x+cosx=0 求sin2x+sinx的值
cos2x+cosx=0 求sin2x+sinx的值
已知sin2x=tanx-cos2x 求sinx-cosx的值
sinx+cosx=1/5,0<x<π,求sinx、cosx、tanx,求sin2x-cos2x的值
已知x∈(0,π),且sinx+cosx=1/2 求sin2x+cos2x,sinx-cosx的值
已知sinx+2cosx=0,求sin2x+cos2x的值
已知1+sinx+cosx+sin2x+cos2x=0,求tanx
已知sinx=-1/2cosx,cosx-sinx/cosx+sinx+sin2x+cos2x的值
cos2x+cosx=0,则sin2x+sinx
sinx+2cosx=0.求cos2x-sin2x/1+cos^x的值
sinx×cos2x-sin2x×cosx
已知2sin2x-cos2x+sinxcosx-6sinx+3cosx=0,求2cosx(sinx+cosx)1+tan
SinX+cosX=3+2根号2,求sin2X+2cos2x分之sin2x+根号2sinx*cosx-cos2x