解方程9^-x-2*3^1-x=27求x=

(x-3)(x-2)+18=(x+9)(x+1)X^-5X+6+18=X^+10X+915X=15X=1

2x²-3x+2x²-2x=4x²-8x+9-5x=-8x+93x=9x=3

(9x-7)/(3x-2)-(4x-5)/(2x-3)=1(9x-7)(2x-3)-(4x-5)(3x-2)=(2x-3)(3x-2)18x²-41x+21-12x²+23x-10

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0

由于【（x+1）-x】/x(x+1)=1/x(x+1)所以1/x(x+1)=1/x-1/(x+1)同理可得：1/(x+1)(x+2)=1/(x+1)-1/(x+2)·····所以原方程可写为：【1/x

两边乘(x+2)(x-1)(x-1)²+9=3(x+2)x²-2x+10=3x+6x²-5x+4=0(x-1)(x-4)=0分母x-2≠0所以x-4=0x=4

方程两边同时乘以x²-1:(3x²+9x+7)(x-1)-(2x²+4x-3)(x+1)-(x³+x+1)=03x^3+9x^2+7x-3x^2-9x-7-(2

9x+7/3x+2-4x+5/2x+3=154x+14x+12-24x+15x+18=659x=-24x=-24/59

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

（1）方程的两边同乘（3x+2）（2x+3），得（9x+7）（2x+3）-（3x+2）（4x+5）=（3x+2）（2x+3），解得x=-1．检验：把x=-1代入（3x+2）（2x+3）=-1≠0，所以

两边乘x(x+3)(x-3)2x³+3x²--27x-x²-3x=5x³-45x-3x³+2x²+27x-18-27x-3x=-45x+27

1/x(x+1)+1/(x+1)(x+2)+.+1/(x+8)(x+9)=(2x+3)/x(x+9)1/x-1/(x+1)+1/(x+1)1/(x+2)+.+1/(x+8)-1/(x+9)=(2x+3

1/x（x+1）+1/（x+1）（x+2）+...+1/(x+8)(x+9)=(1/x-1/x+1)+(1/x+1-1/x+2)+...+(1/x+8-1/x+9)=1/x-1/x+9=9/x(x+9

(3x+1)(3x-1)=(x+2)(9x-4)9x^2-1=9x^2+14x-8-14x=-7x=1/22(x-3)(x-2)-(x+3)²=(x-1)(x+1)2(x^2-5x+6)-(

两边各自通分得：6/[(x+2)(x+8)]=6/[(x+3)(x+9)]因此有(x+2)(x+8)=(x+3)(x+9)展开即x^2+10x+16=x^2+12x+272x=-11x=-5.5经检验

(-3x-1/2)(1/2-3x)=x(9x-1/5)(-3x-1/2)(-3x+1/2)=x(9x-1/5)(-3x)²-(1/2)²=9x²-x/59x²-

你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你

解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2