用两种方法计算(x-2分之3x-x 2分之x)×x分之x的平方-4

=3/3x-2/3x+x/(3x-2)=1/3x+x/(3x-2)=(3x-2+3x²)/3x(3x-2)=(3x²+3x-2)/(9x²-6x)

原式=[(2x-6)/(x^2-4x+4)]/(x+3)*(x^2+x-6)/(3-x)=[2(x-3)/(x-2)^2]/(x+3)*(x+3)(x-2)/(3-x)=-2/(x-2)

x^2/(x-3)-(2x-3)/(3-x)+(2x+6)/(3-x)=x^2/(x-3)+(2x-3)/(x-3)-(2x+6)/(x-3)=[x^2+(2x-3)-(2x+6)]/(x-3)=(x

(x-2)/(x+3)÷[x-3+5/(x+3)]=(x-2)/(x+3)÷[(x-3)(x+3)+5]/(x+3)=(x-2)/(x+3)÷[(x²-9+5)/(x+3)]=(x-2)/(

3又20分之7×101-0.35=3.35×（100+1）-0.35=335+0.35-0.35=3352分之x-3分之x=1.26分之x=1.2x=1.2×6x=7.2祝开心

原式=(x^2+3x)/(x^2+x-6)-(x+2)/(x^2-4)=x(x+3)/(x+3)*(x-2)-(x+2)/(x+2)*(x-2)=x/(x-2)-1/(x-2)=(x-1)/(x-2)

使用公式编辑器写清楚,这种题靠文字事不易表述清楚的.

1.计算：x-y分之x+y+y-3分之2x=(x+y)/(x-y)+2x/(y-3)=((x+y)(y-3)+2x(x-y))/(x-y)(y-3)=(xy-3x+y^2-3y+2x^2-2xy)/(

（x-2)(x-3)+(x-4)(x-5)+(x-2)(x-4)+(x-3)(x-5)=（x-2)(x-3)+(x-2)(x-4)+(x-4)(x-5)+(x-3)(x-5)=(x-2)(x-3+x-

5(x-3)分之4x-2(3-x)分之x=5(x-3)分之4x+2(x-3)分之x=10(x-3)分之(8x+5x)=10(x-3)分之13x明白请采纳,有新问题请求助,

能原等式=(x-y)/(x+y)=(3x-3y)/(3x+3y)=(2y-3y)/(2y+3y)=-1/5再问：亲，我有答案，不知怎么做，结果跟你不对，结果是-5再答：我看错了，写反了，原式=(x+y

原式=x(x²-2x+3-3)×2/x²=x²(x-2)×2/x²=2x-4

x（x-1）分之1+(x-1)(x-2)分之1+(x-2)(x-3)分之1+...+（x-99）（x-100）分之1=1/(x-1)-1/x+1/(x-2)-1/(x-1)+...+1/(x-100)

化简：原式=x^2/2-2x+2=1/2(x^2-4x+4)=1/2(x-2)^2

[(x-2)分之3x-2分之x]×x分之(x²-4)=[2(x-2)分之6x-2(x-2)分之(x²-2x)]×x分之[(x+2)(x-2)]=2(x-2)分之(4x-x²

原式=2x/(x^2-4)-1/(2-x)+3/(x+2)=2x/(x-2)(x+2)+1/(x-2)+3/(x+2)=[2x+(x+2)+3(x-2)]/(x-2)(x+2)=(6x-4)/(x-2

解原式=3(2-x)/3(x-4)(x+2)+(x+4)(x-4)/3(x+2)(x-4)=(6-3x)/3(x-4)(x+2)+(x²-16)/3(x+2)(x-4)=(6-3x+x

先分别把第1、2项合并,第3、4项合并,最后加总,原式=[(5x+10)-(3x-3)]/[(x^2+x)-2]-[(5x+15)-(3x-6)]/[(x^2+x)-6]=(2x+13)/[(x^2+

原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18

注:分子/分母(1/x-3)+(1/9-x^2)-(x-1/6-2x)通分:=2(x+3)/2(x+3)(x-3)+12/2(9-x^2)-(x-1)(3+x)/2(3-x)(3+x)=2x+6/2(