cos2x除以sin3x的积分等于什么
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∫cos2x/(cos²x*sin²x)dx=∫cos2x/(cosx*sinx)²dx=∫cos2x/(1/2*2sinx*cosx)²dx=∫cos2x/[
第一种方法的原理:只要令x = π/2 - u,∫(0→π/2) sinⁿx dx和∫(0→π/2) cos̿
∫(0,π)根号(1+cos2x)dx=∫(0,π)根号(2cosx^2)这里要把根号开出来得分正负了(cosx在0,π/2上大于0,在π/2,π上小于0)原式=∫(0,π/2)*根号2cosx-∫(
二分之根号2乘以arctan[(x-1)/根号(2x)]+四分之根号2乘以lnabs[(x+根号2x+1)/(x-2x+1)]+C
如图再问:第二题呢?再答:第二题不会啊
∫π/20(cos2x/cosx+sinx)dx=∫π/20(cos²x-sin²x)/(cosx+sinx)dx=∫π/20(cosx-sinx)dx=sinx+cosxπ/20
我有个疑惑,这个命题成立吗?左边=sinx+2sinxcosx+3sinx(cosx)^2-(sinx)^3=4sinx(cosx)^2+2sinxcosx=2sinxcosx(2cosx+1)=2s
cos2x=(cosx)^2-(sinx)^2=2(cosx)^2-1(cosx)^2=(1+cos2x)/2再问:为什么cos2x=(cosx)^2-(sinx)^2再答:cos(A+B)=cosA
(3sin2x+4cos2x)/(cos2x-3sin2x)用万能公式sin2x=2tanx/(1+tan²x)=4/5cos2x=(1-tan²x)/(1+tan²x)
sin3xsin^3x+cos3xcos^3-(cos2x)^3=sin2xcosxsin^3x+cos2xsin^4x+cos2xcos^4x-sin2xsinxcos^3x-(cos2x)^3=(
sin^3x表示sinx三次方sin3xsin^3x+cos3xcos^3x=sin2xcosxsin^3x+cos2xsin^4x+cos2xcos^4x-sin2xsinxcos^3x=1/2(s
-1/2*pi 1/2*pi 2/3*pi -2/3*pi 0
2*(sin(x))^3*cos(2*x)+2*(sin(x))^2=0解析:左式=2*(sin(x))^3*(1-2(sin(x))^2)+2*(sin(x))^2=2*(sin(x))^3-4*(
1.左边=sin3x*sinx*(sinx)^2+cos3x*cosx*[1-(sinx)^2]=-(sinx)^2*cos4x+cos3x*cosx=-(sinx)^2*cos4x+(cos4x+c
sinxsin3xsin2x=-1/2(cos4x-cos2x)sin2x=1/2(sin2xcos4x-sin2xcos2x)=1/2*[1/2(sin6x-sin2x)-1/2sin4x]=1/4
sin3xsin^3x+cos3xcos^3x=sin2xcosxsin^3x+cos2xsin^4x+cos2xcos^4x-sin2xsinxcos^3x=1/2(sin^2(2x)sin^2x-
cos(A+B)=cosAcosB-sinAsinB再问:为什么啊?再答:公式就是这样的...再问:必修4上的吗?再答:是的啊
cos2x=2cos(^2)x-1所以被积函数化为2(^0.5)cosx的绝对值,最后得2*2(^0.5)